Given a linked list, determine if it has a cycle in it.
Follow up:
Can you solve it without using extra space?
Can you solve it without using extra space?
Analysis:
Use a fast and slow pointer and list has a cycle if two pointers encounter.
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
bool hasCycle(ListNode *head) {
ListNode* fast = head;
ListNode* slow = head;
while(fast != NULL && fast->next != NULL)
{
fast = fast->next->next;
slow = slow->next;
if (fast == slow)
break;
}
return fast != NULL && fast->next != NULL;
}
};
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