Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum.
For example:Given the below binary tree and
sum = 22
,5 / \ 4 8 / / \ 11 13 4 / \ / \ 7 2 5 1
return
[ [5,4,11,2], [5,8,4,5] ]Analysis:
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
void helper(TreeNode *root, int sum, vector<vector<int> >& ret, vector<int>& nums)
{
if (root == NULL)
return;
//have to be leaft
else if (root->left == NULL && root->right == NULL && sum == root->val)
{
//leaf number was not pushed yet
nums.push_back(root->val);
ret.push_back(nums);
nums.pop_back();
}
else
{
nums.push_back(root->val);
helper(root->left, sum - root->val, ret, nums);
helper(root->right, sum - root->val, ret, nums);
nums.pop_back();
}
}
vector<vector<int> > pathSum(TreeNode *root, int sum) {
vector<vector<int> > ret;
vector<int> nums;
helper(root, sum, ret, nums);
return ret;
}
};
No comments:
Post a Comment